If it's not what You are looking for type in the equation solver your own equation and let us solve it.
324=2a^2
We move all terms to the left:
324-(2a^2)=0
a = -2; b = 0; c = +324;
Δ = b2-4ac
Δ = 02-4·(-2)·324
Δ = 2592
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2592}=\sqrt{1296*2}=\sqrt{1296}*\sqrt{2}=36\sqrt{2}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36\sqrt{2}}{2*-2}=\frac{0-36\sqrt{2}}{-4} =-\frac{36\sqrt{2}}{-4} =-\frac{9\sqrt{2}}{-1} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36\sqrt{2}}{2*-2}=\frac{0+36\sqrt{2}}{-4} =\frac{36\sqrt{2}}{-4} =\frac{9\sqrt{2}}{-1} $
| 5x=(3x+4) | | 2.x-7=21 | | 5t-18=6t | | 3*x(-1.2)+9.6=0 | | 7x-(8+5x)=12 | | 2(x+3)-4(x+2)=6 | | 4x-7(11-6x)=-8 | | 3m+4-10+2m=4 | | 0.75^t=0.5 | | A(x)=1,39*x+20,16 | | 5(t-2)=4(t+15) | | |15-9x=48| | | 9-(7-8x)=3 | | 4x+1/3=x-5/12 | | X+280=y | | |15-6x|=48 | | 20-5x/5=18 | | (5x-1)+4=2(x+3)-1 | | 6x–18=6x–12 | | 12x^2–9x=0 | | 6x–12=3x–12 | | 4+7x=2x-11 | | 14=-4(9x-1 | | 0=5(3q-11)-5 | | (2x-5)(-3x-6)=0 | | 6x^2+6x+36=36 | | 5(5y÷6)-4y=8 | | 2y(2y+8=) | | 5x-100=9000 | | 14,000+160x=24,000-200x | | 7x+2x=12+14 | | 4x+80=500 |